What is the derivative of #ln(x^3)#?

1 Answer
May 25, 2015

We can use the chain rule here, which states that

#(dy)/(dx)=(dy)/(du)(du)/(dx)#

Thus, as it's not possible to directly derivate #ln(x^3)#, we can rename #u=x^3# and proceed to derivate #ln(u)# following chain rule's steps.

#(dy)/(du)=1/u#
and
#(du)/(dx)=3x^2#

Now, aggregating both parts, as stated by the chain rule:

#(dy)/(dx)=1/u*3x^2=1/x^cancel(3)*3cancel(x^2)=color(green)(3/x)#