What is the derivative of #pi / (9x)^2#?
1 Answer
Jan 30, 2017
#d/dx pi/(9x)^2 = (-2pi)/(81x^3)#
Explanation:
#d/dx pi/(9x)^2 = d/dx pi/(81x^2)#
# " " = pi/81 d/dx 1/x^2#
# " " = pi/81 d/dx x^(-2)#
# " " = pi/81 (-2) x^(-2-1)#
# " " = (-2pi)/81 x^(-3)#
# " " = (-2pi)/(81x^3)#