Question

What is the derivative of `sec(x^2-4)`?

Answer 1

`f'(x)=2xsec(x^2-4)tan(x^2-4)`

Explanation:

to find derivative of `f(x)=sec(x^2-4)`, we know that `d/(dx) secx=secxtanx`

Hence `f'(x)=sec(x^2-4)tan(x^2-4)xx2x` or

`f'(x)=2xsec(x^2-4)tan(x^2-4)`