What is the derivative of #sin x^2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer AltairSafir Mar 28, 2018 I assume #f(x)=sin(x^2)# Explanation: #f^'(x)=(sin(x^2))^'=cos(x^2)*(x^2)^'=cos(x^2)*2*x=2xcos(x^2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1527 views around the world You can reuse this answer Creative Commons License