What is the derivative of #sqrtthetasintheta#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Eddie Jun 27, 2016 #= (1/(2 sqrt theta)) sin theta + sqrt theta cos theta # Explanation: #(sqrt (theta) sin (theta))'# from product rule #= (sqrt theta)' sin theta + sqrt theta (sin theta)' # #= 1/(2 sqrt theta) sin theta + sqrt theta cos theta # Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1600 views around the world You can reuse this answer Creative Commons License