What is the derivative of sqrtthetasintheta?

Jun 27, 2016

Answer:

$= \left(\frac{1}{2 \sqrt{\theta}}\right) \sin \theta + \sqrt{\theta} \cos \theta$

Explanation:

$\left(\sqrt{\theta} \sin \left(\theta\right)\right) '$

from product rule
$= \left(\sqrt{\theta}\right) ' \sin \theta + \sqrt{\theta} \left(\sin \theta\right) '$

$= \frac{1}{2 \sqrt{\theta}} \sin \theta + \sqrt{\theta} \cos \theta$