# What is the derivative of #(x + 1)/y#?

##### 1 Answer

Aug 15, 2015

#### Explanation:

Use the quotient rule and the chain rule. (all implicit differentiation uses the chain rule.)

There's not much more we can do without the rest of the equation relating

We could rewrite a bit, to get:

# = ( y-(x+1) dy/dx)/y^2#

or

# = 1/y - (x+1)/y^2 dy/dx#