What is the derivative of #(x^2+3)/x#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Eddie Jul 5, 2016 #=1- 3/x^2# Explanation: #((x^2+3)/x)^prime# #=(x+3/x)^prime# #=1+(3/x)'# #(3/x)' = (3x^{-1})' = (-1) 3 x^{-2} = - 3/x^2# #=1- 3/x^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1164 views around the world You can reuse this answer Creative Commons License