What is the derivative of # (x^2+x)^2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ May 21, 2015 I would use the Chain Rule to derive the #()^2# first and then the argument as in: #y'=2(x^2+x)^(2-1)*(2x+1)=2(x^2+x)(2x+1)=2x(x+1)(2x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1208 views around the world You can reuse this answer Creative Commons License