Question

What is the derivative of `y= 2x^4 - 2x^3 - 8`?

Answer 1

I found: `y'=8x^3-6x^2`

Explanation:

You can use the fact that the derivative of `y=x^n` is:
`y'=nx^(n-1)` to get:
`y'=2*4x^(4-1)-2*3x^(3-1)-0=8x^3-6x^2`