What is the derivative of y=ln[x/(2x+3)]^(1/2)? Calculus Differentiating Logarithmic Functions Overview of Different Functions 1 Answer Sasha P. Oct 17, 2015 y' = 3/(2x(2x+3)) Explanation: y=ln[x/(2x+3)]^(1/2) = 1/2 ln[x/(2x+3)] y'=1/2 * 1/(x/(2x+3)) * (2x+3-2x)/(2x+3)^2 = 3/(2x(2x+3)) Answer link Related questions How do you find the derivative of y=sin2x+cos2x+ln(ex)? What is the derivative of y= e^(3x/4)? What is the derivative of y= 2x^4 - 2x^3 - 8? What is the derivative of e^(x^3)+log_5(pi)? What is the derivative of ln(x^2)? What is the derivative of 1/logx? Question #b5198 Question #09fd4 Question #56c3f See all questions in Overview of Different Functions Impact of this question 3167 views around the world You can reuse this answer Creative Commons License