Question

What is the derivative of `y=5^sqrt(s)`?

Answer 1

`dy/(ds)=(log(5)5^sqrt(s))/(2sqrt(s))`

Explanation:

Use the chain use:

`f(x)=g(h(x))=>f'(x)=h'(x)g'(h(x))`

With:
`g(u)=5^u=>g'(u)=log(5)5^u`
`h(x)=sqrt(x)=>1/(2sqrt(x))`

Putting this together we have:
`dy/(ds)=(log(5)5^sqrt(s))/(2sqrt(s))`