What is the derivative of #y = arcsin(y^5)#?
1 Answer
Feb 26, 2016
Explanation:
using the
#color(blue) " chain rule " # and
#d/dx(sin^(-1) x) = 1/sqrt(1 - x^2)# hence
#d/dy(sin^(-1)(y^5)) = 1/sqrt(1 - (y^5)^2) .d/dy(y^5)#
# = (5y^4)/sqrt(1 - y^10) #
