# What is the derivative of y=e^(-1)?

Aug 5, 2014

y = ${e}^{- 1}$ is a constant function.
See, ${e}^{- 1} = \frac{1}{e}$ and there's no x in the expression.

The derivative of any constant is zero.

So $\frac{\mathrm{dy}}{\mathrm{dx}} = 0.$

Unless… the letter e has been defined as a variable, and the question is to find $\frac{\mathrm{dy}}{\mathrm{de}} .$ Then the derivative would be $- \frac{1}{{e}^{2}}$. But that seems unlikely.

\dansmath to the rescue!/