What is the derivative of #y=e^(-1)#?

1 Answer
Aug 5, 2014

y = #e^(-1)# is a constant function.
See, #e^(-1) = 1/e# and there's no x in the expression.

The derivative of any constant is zero.

So #dy/dx = 0.#

Unless… the letter e has been defined as a variable, and the question is to find #dy/(de).# Then the derivative would be #-1/(e^2)#. But that seems unlikely.

\dansmath to the rescue!/