# What is the derivative of y= -e^(x^2+x-3) ?

Nov 15, 2015

$- \left(2 x + 1\right) {e}^{{x}^{2} + x - 3}$

#### Explanation:

According to the Chain Rule, the derivative of ${e}^{u}$ is equivalent to $u ' {e}^{u}$.

So, we can say that $y ' = - \frac{d}{\mathrm{dx}} \left[{x}^{2} + x - 3\right] \cdot {e}^{{x}^{2} + x - 3}$.

We can calculate that $\frac{d}{\mathrm{dx}} \left[{x}^{2} + x - 3\right] = 2 x + 1$.

Now, we plug the value of the derivative back into the equation we found from the chain rule to determine that color(red)(y'=-(2x+1)e^(x^2+x-3)