Question

What is the derivative of `y= log (6x-2)`?

Answer 1

`dy/dx=6/(ln(10)(6x-2))`

Explanation:

Assuming `log(6x-2)=log_{10}(6x-2)`, the Chain Rule and the fact that `d/dx(log_{10}(x))=1/(ln(10)x)` imply that

`dy/dx=6/(ln(10)(6x-2))` when `y=log(6x-2)`.