What is the derivative of #y = log3 [(x+1/x-1)^ln3]#?
1 Answer
Sep 11, 2015
I will guess that this should be:
Explanation:
So we get:
# = (1-1/x^2)/(x+1/x-1)#
# = (x^2-1)/(x^2-x+1)#
Note if the original should have been
Then we get
and