# What is the derivative of y = [(x-2)/k]^(1/2) where k is a constant?

Oct 20, 2017

Look below.

#### Explanation:

where $k \ne 0$

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{1}{2} {\left[\frac{x - 2}{k}\right]}^{- \frac{1}{2}} \cdot \frac{d}{\mathrm{dx}} \left(\frac{x - 2}{k}\right)$

$= \frac{1}{2} {\left[\frac{x - 2}{k}\right]}^{- \frac{1}{2}} \cdot \left(\frac{1}{k}\right)$

=1/(2sqrt(k(x-2))