What is the derivative of #y = x^2 ln(2x)#?

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#y = x^2 ln(2x)#

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Answer 1 · 2017-10-22T04:53:30

see below.

#y=x^2ln(2x)#

#dy/dx=x^2d/dxln(2x)+ln(2x)d/dxx^2#

#=x^2(1/2x)d/dx2x+ln(2x)(2x)#

#=x/2*2+2xln(2x)#

#=x+2xln(2x)#