What is the derivative ? y= [(6-5x)/(x^2-1)]^2

1 Answer
Mar 8, 2018

y' = 2((6-5x)/(x^2-1)) * ((5x^2 - 12x + 5)/(x^2-1)^2)

Explanation:

y = ((6-5x)/(x^2-1))^2

y' = 2((6-5x)/(x^2-1)) * ((-5(x^2 - 1) - (6-5x)(2x))/(x^2-1)^2)

y' = 2((6-5x)/(x^2-1)) * ((-5x^2 + 5 - 12x+10x^2)/(x^2-1)^2)

y' = 2((6-5x)/(x^2-1)) * ((5x^2 - 12x + 5)/(x^2-1)^2)