What is the discriminant of: #x^2-4x+10=0#?

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Answer 1 · 2018-03-13T14:55:15

#-24#

In the quadratic formula #x=(-b+-sqrt(b^2-4ac))/(2a)#
the discriminant is the value under the radical (square root sign).

The letters #a#, #b#, and #c# represents the coefficients of each term.

In this case, #a=1#, #b=-4# and #c=10#

Plug this into the formula:

#sqrt((-4)^2-4(1)(10)#

#=sqrt(16-40)#

#=sqrt(-24)#

The discriminant is #-24#