What is the discriminant of #x^2 - 5x = 6# and what does that mean?
For a quadratic equation that has the general form
#color(blue)(ax^2 + bx + c = 0)#
the discriminant can be calculated by the formula
#color(blue)(Delta = b^2 - 4 * a * c)#
Rearrange your quadratic by adding
In your case, you have
The general form of the two solutions is given by the quadratic formula
#color(blue)(x_(1,2) = (-b +- sqrt(Delta))/(2a)#
In your case, these two solutions will be
In this case, (a - b + c = 0), use the shortcut --> 2 real roots--> - 1 and
REMINDER of SHORCUT
When (a + b + c = 0) --> 2 real roots: 1 and
When (a - b + c = 0) --> 2 real roots: - 1 and
Remember this shortcut. It will save you a lot of time and effort.