What is the discriminant of #x^2 + 8x + 16 = 0# and what does that mean?

1 Answer
Jul 23, 2015

Answer:

The expression is of the form #Ax^2+Bx+C=0#
where #A=1,B=6,C=16#

Explanation:

The discriminant is defined as #D=B^2-4AC#
If #D>0# there are two solutions to the equation
If #D=0# there is one solution
If #D<0# there is no solution (in real numbers)

In your case #D=8^2-4*1*16=0->#one solution.

The equation can be written as #(x+4)^2->x=-4#