What is the distance between the following polar coordinates?: (-1,(pi)/2), (2,(15pi)/12)

1 Answer
Mar 11, 2018

I left explanation, try to finish it

Explanation:

In Euclidean geometry, we have where dl is the distance, we have:
dl^2 = dx^2 + dy^2

In polar coordinates:
x = r*cos(theta)
dx = drcos(theta) - rsin(theta)d theta

y = r*sin(theta)
dy = drsin(theta) + rcos(theta)d theta

Plug into the first formula and you get the answer:)

Distance between 2 coordinates in polar coordiantes is given by:
l = sqrt((r_2-r_1)^2 + r^2(theta_1 - theta_2))