# What is the domain and range of #f(x) = 1/(1+x^2)#?

##### 1 Answer

Aug 3, 2015

Domain:

Range:

#### Explanation:

The only possible restriction for this function's domain is when the denominator is equal to **zero**, but since **always** be positive.

This means that the domain of the function will be

Since the denominator will **always** be positive, **always** be positive as well.

The range of the function will be

*global maximum*

That happens because you have

The range of the function will thus be

graph{1/(1+x^2) [-8.89, 8.89, -4.444, 4.445]}