Question

What is the domain and range of `f(x)= 1/(x+1)`?

Answer 1

`x!=-1andy!=0`

Explanation:

If `x=1` the denominator of the fraction would be `=0` which is not allowed.
If `x` becomes larger the function would get nearer to `0` without getting there.

Or, in "the language":

`lim_(x->-1+) f(x)= oo and lim_(x->-1-) f(x)= -oo`

`lim_(x->+- oo) f(x)=0`
graph{1/(x+1) [-10, 10, -5, 5]}