Question

What is the domain and range of `g(x)=(1-x^2)`?

Answer 1

domain would be (-infinity to infinity)

Answer 2

The domain would be unlimited, as there are no 'forbidden' values for `x` (no fractions, no roots).
Domain `=(-oo,+oo)`

Explanation:

For the range we observe that the maximum value of `g(x)` happens when `x=0` (which means the least to subtract from 1).
Any other value of `x` would make `x^2>0->g(x)<1`
Range `=(-oo,1]`