What is the domain and range of #g(x)=(1-x^2)#?

2 Answers
Ashish R.
Mar 1, 2016

domain would be (-infinity to infinity)

MeneerNask
Mar 1, 2016

The domain would be unlimited, as there are no 'forbidden' values for #x# (no fractions, no roots).
Domain #=(-oo,+oo)#

Explanation:

For the range we observe that the maximum value of #g(x)# happens when #x=0# (which means the least to subtract from 1).
Any other value of #x# would make #x^2>0->g(x)<1#
Range #=(-oo,1]#

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