What is the domain and range of #ln(x - 3) + 2#?

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Answer 1 · 2016-06-19T08:01:17

Domain is #(3,+oo)# and range is #RR#

The domain is obtained by solving

#x-3>0#

#x>3#

Let be #y=ln(x-3)+2#

#ln(x-3)=y-2#

#x-3=e^(y-2)#

#x=e^(y-2)+3#

that is calculated for all y

so the range of y is #RR#