Question

What is the domain and range of `x=(y+2)^2`?

Answer 1

Domain would be [0, `oo`) and Range would be [-2,`oo`)

Explanation:

The function would either be y+2=`sqrt x` or -`sqrtx`. If y+2= `sqrt x` is the function, it would represent the upper portion of a horizontal parabola, with its vertex at (0,-2).

Domain would be [0, `oo`) and Range would be [-2,`oo`)