# What is the domain and range of #y = 1/(x^2 - 2)#?

##### 1 Answer

#### Answer:

Domain:

Range:

#### Explanation:

The only restriction to the domain of the function will occur when the denominator is equal to **zero**. More specifically,

These two values of *excluded* from the function's domain.

No other restrictions apply, so you can say that the domain of the function is

This restriction on the possible values

Because you don't have a value of

Simply put, because you have

the range of the function will be

In other words, the function's graph will have two *vertical asymptotes* at

graph{1/(x^2-2) [-10, 10, -5, 5]}