What is the domain and range of $y=secx$ ?

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Answer 1 · 2017-11-25T11:31:07

Domain: $x in RR | x != (npi+pi/2)$
Range: $y <= -1 uu y>=1 or y| (-oo,-1)uu(1,oo)$

$y=sec x or y= 1/cosx :. sec x$ is undefined at $cosx=0$

$cos (npi+pi/2)=0 :. x != (npi+pi/2)$ Thus, the domain of the

secant function is the set of real numbers excluding

$x = (npi+pi/2)$ i.e Domain: $x in RR | x != (npi+pi/2)$

Range: cosine function only takes values that are between $−1$ and

$+1$ . So $secx$ can only take values that are $>=1 or <=-1 :.$

Range: $y <= -1 uu y>=1 or y| (-oo,-1)uu(1,oo)$

graph{secx [-10, 10, -5, 5]} [Ans]

What is the domain and range of y=secx y=secx?