# What is the domain and range of y =sqrt(tanx)?

Jul 5, 2018

Domain: ${\cup}_{k \in \mathbb{Z}} \left[k \pi , \frac{\pi}{2} + k \pi\right)$

Range: ${\mathbb{R}}_{+}$

#### Explanation:

$\tan x \ge 0$

$x \in \left[0 , \frac{\pi}{2}\right) + k \pi$