What is the domain of #f(x) = (3x-1) / (x^2-x) #?
1 Answer
Sep 7, 2015
Domain:
Explanation:
Right from the start, you know that the domain of the function must not include any value of
So basically, any value of
#x^2 - x != 0#
wil be excluded from the function's domain.
You can rewrite this equation like this
#x^2 - x = 0#
#x * (x-1) = 0 implies {(x=0), (x=1) :}#
This means that the domain of the function will be
graph{(3x - 1)/(x^2 - x) [-46.22, 46.22, -23.1, 23.15]}