# What is the domain of #f(x) = (3x-1) / (x^2-x) #?

##### 1 Answer

Sep 7, 2015

#### Answer:

Domain:

#### Explanation:

Right from the start, you know that the domain of the function must **not include** any value of

So basically, any value of

#x^2 - x != 0#

wil be excluded from the function's domain.

You can rewrite this equation like this

#x^2 - x = 0#

#x * (x-1) = 0 implies {(x=0), (x=1) :}#

This means that the domain of the function will be

graph{(3x - 1)/(x^2 - x) [-46.22, 46.22, -23.1, 23.15]}