What is the dot product of #<-1,-2,1># and #<-1, 2,3 >#?

1 Answer
Mar 17, 2018

Answer:

The dot product is #=0#

Explanation:

The dot product of #2# vectors # < x_1,x_2,x_3># and #< y_1,y_2,y_3 ># is

#< x_1,x_2,x_3> .< y_1,y_2,y_3 > = x_1y_1+x_2y_2+x_3y_3#

Therefore,

#< -1, -2, 1> .< -1, 2, 3 > = (-1)*(-1)+ (-2)*(2)+(1)*(3) #

#=1-4+3#

#=0#

As the dot product is #=0#, the vectors are orthogonal.