What is the energy difference between the two quantum states involved in the transition of red light with wavelength 705 nm being absorbed by an atomic gas?

1 Answer
Jun 22, 2015

Answer:

I found:
#E=h*nu=2.82xx10^-19J=1.76eV#

Explanation:

A wavelength of #705 nm# corresponds to a frequency:
#nu=c/lambda=(3xx10^8)/(7.05xx10^-7)=4.25xx10^14Hz#

From Einstein's Relatonship you have that the photon energy will be:

#color(red)(E=h*nu)=6.63xx10^-34*4.25xx10^14=2.82xx10^-19J=1.76eV#

This is exactly the energy gap (or difference) between the two quantum states involved in the absorption of your photon of red light.