What is the equation in point-slope form and slope intercept form for the line given (-3,6) and (2,-9)?

1 Answer
May 4, 2015

The point-slope form is y-6=3(x+3)y6=3(x+3), and the slope-intercept form is y=3x+15y=3x+15 .

Determine the slope, mm.

m=(y_2-y_1)/(x_2-x_1)m=y2y1x2x1 .

Let (-3,6)=x_1,y_1(3,6)=x1,y1 and (2,-9)=x_2,y_2(2,9)=x2,y2 .

m=(-9-6)/(2-(-3))=15/5=3m=962(3)=155=3

Point-slope Form

The general formula is y-y_1=m(x-x_1)yy1=m(xx1)

Use one of the points given as x_1x1 and y_1y1. I'm going to use point (-3,6)(3,6) which is consistent with finding the slope.

x_1=-3x1=3
y_1=6y1=6
m=3m=3.

y-6=3(x-(-3))y6=3(x(3)) =

y-6=3(x+3)y6=3(x+3)

Slope-intercept Form

The general formula is y=mx+by=mx+b, where mm is slope and bb is the y-intercept.

Solve the point-slope form equation for yy.

y-6=3(x+3)y6=3(x+3)=

Add 66 to both sides.

y=3(x+3)+6y=3(x+3)+6 =

Distribute the 33.

y=3x+9+6y=3x+9+6 =

y=3x+15y=3x+15

The slope is 33 and the yy-intercept is 1515.