# What is the equation in point-slope form of the line given (-2,3); m=-1?

May 8, 2015

You can use the relationship:
$y - {y}_{0} = m \left(x - {x}_{0}\right)$
With:
$m = - 1$
${x}_{0} = - 2$
${y}_{0} = 3$
If you have difficulty have a look at the solution below.
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Solution:
$y - 3 = - 1 \left(x + 2\right)$

That can also be written as:
$y = - x - 2 + 3$
$y = - x + 1$

May 8, 2015

The answer is $y - 3 = - 1 \left(x + 2\right)$.

Determine the point-slope form of a line passing through the point $\left(- 2 , 3\right)$ with slope, $m$ of $- 1$.

Generic point-slope form is $y - {y}_{1} = m \left(x - {x}_{1}\right)$ .

For point $\left(- 2 , 3\right)$, ${y}_{1} = 3$, ${x}_{1} = - 2$

Point-slope for given point and slope.

$y - 3 = - 1 \left(x - \left(- 2\right)\right)$ =

$y - 3 = - 1 \left(x + 2\right)$