What is the equation of a circle whose center is at the origin and whose radius is 16?

1 Answer
Mar 2, 2016

Polar form: r = 16.
Cartesian form: r = $\sqrt{{x}^{2} + {y}^{2}}$ = 16 or $\left({x}^{2} + {y}^{2}\right)$ = ${16}^{2}$

Explanation:

Points on a circle are equidistant from its center. This distance is called the radius of the circle.