**Step 1**: You have two points in your question: #(2,2)# and #(3,6)#. What you need to do, is use the slope formula. The slope formula is

#"slope" = m = (y_2-y_1)/(x_2-x_1)#

**Step 2**: So let's look at the first point in the question. #(2,2)# is #(x_1,y_1#. That means that #2= x_1# and #2= y_1#. Now, let's do the same thing with the Second point #(3,6)#. Here #3= x_2# and #6= y_2#.

**Step 3**: Let's plug those numbers into our equation. So we have

#m = (6-2)/(3-2) = 4/1#

That gives us an answer of #4#! And the slope is represented by the letter #m#.

**Step 4**: Now let's use our equation of a line formula. That slope-intercept equation of a line is

#y= mx+b#

**Step 5**: Plug in one of the points: either #(2,2)# or #(3,6)# into #y= mx+b#. Thus, you have

#6= m3+b#

Or you have

#2= m2+b#

**Step 6**: You have #6= m3+b# OR you have #2= m2+b#. We also found our m earlier in step 3. So if you plug in the #m#, you have

#6= 4(3)+b" " or " "2= 4(2)+b#

**Step 7**: Multiply the #4# and #3# together. That gives you #12#. So you have

#6= 12+b#

Subtract the #12# from both sides and you now have

#-6=b#

OR

Multiply #4# and #2# together. That gives you #8#. So you have

#2= 8+b#

Subtract #8# from both sides and you now have

#-6=b#

**Step 8**: So you have found #b# and #m#! That was the goal! So your equation of a line that goes through #(2,2)# and #(3,6)# is

#y=4x-6#