What is the equation of the line between #(1,3)# and #(-4,1)#?

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Answer 1 · 2016-06-30T09:09:24

Its equation is ; #5y = 2x + 13#

first you will find its gradient ( slope );

gradient = #(y_1 - y_2)/(x_1-x_2)# or #(y_2 - y_1)/(x_2-x_1)#

{I am applying the first one]

gradient =#( 3-1)/(1-(-4))#

gradient = #2/5#

now put gradient , in this equation

y = m*x + c

{where m is gradient & c is y-intercept (where x is 0) }

#y = (2/5)*x + c#

{now put the value of y and x, either use first point or the second one i.e. (1, 3) or (-4, 1) }

#3 = (2/5)* 1 +c#
#3-(2/5) = c#
#13/5 = c#

{c is found now put m and c in the equation y = mx + c}

#y = (2/5)*x + 13/5#

#5 y= 2x + 13 #

{you can put any two points and the answer will be the same}

equation found...!