What is the equation of the line normal to #f(x)= -1/(5-x^2) # at #x=-3#?
Equation of line normal is
Slope of the tangent of a curve, at a given point, is given by the value of the first derivative at that point. As normal is perpendicular to tangent, if
To find the point, let us put
Hence, we are seeking normal at
Hence slope of tangent at
and slope of normal is
and equation of line normal is