Question

What is the equation of the line perpendicular to `-x+y=7` and passing through `(-1, -1)`?

Answer 1

The equation of line in point `(-1,-1)` slope form is `y+1 = -(x+1)`

Explanation:

The slope of the line `-x+y=7or y= x+7 [y=m_1x+c]` is `m_1=1`

The product of slopes of two perpendicur lines is `m_1 *m_2=-1 :. m_2 =-1/m_1 = -1/1=-1`

The equation of line in point `(-1,-1)` slope form is `y-y_1 = m_2(x-x_1) or y +1 = -1(x+1) or y+1 = -(x+1)` [Ans]