What is the equation of the line perpendicular to $y=-23x$ that passes through $(-1,-6)$ ?

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Answer 1 · 2015-12-27T15:51:31

The slope of a perpendicular line is always the negative reciprocal of the other line's slope.

If the slope of y = -23x is -23, the slope of the perpendicular line is $1/23$ .

y - (-6) = $1/23$ (x - (-1)

y = $1/23x$ + $1/23$ - 6

y = $1/23x$ - $137/23$

y = $1/23x$ - $137/23$ is the equation of the line perpendicular to y = -23x and that passes through (-1, -6).

Hopefully you understand now!

What is the equation of the line perpendicular to y=-23x y=-23x that passes through (-1,-6) (-1,-6) ?