# What is the equation of the line perpendicular to y=-3/8x  that passes through  (-8,8) ?

Jul 6, 2016

$y = \frac{8}{3} x + 29 \frac{1}{3}$

#### Explanation:

If lines are perpendicular, then the slope of one is the negative reciprocal of the other.

So, $\frac{1}{2}$ is perpendicular to $- 2$

$- \frac{2}{3}$ is perpendicular to $\frac{3}{2}$

$\frac{5}{4}$ is perpendicular to $- \frac{4}{5}$

In this case, $\text{ } - \frac{3}{8}$ is perpendicular to $\frac{8}{3}$

We also have the point $\left(- 8 , 8\right)$

Use the formula $\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

$y - 8 = \frac{8}{3} \left(x - \left(- 8\right)\right)$

$y = \frac{8}{3} x + \frac{64}{3} + 8$

$y = \frac{8}{3} x + 29 \frac{1}{3}$