Question

What is the equation of the line perpendicular to `y=9/16x` that passes through `(-1,5)`?

Answer 1

`y = -16/9x+3 2/9`

Explanation:

A line perpendicular to `y = 9/16x` will have a slope of `-16/9`

So, with `m = -16/9 and (-1,5)` we can find the equation from:

`y-y_1 = m(x-x_1)`

`y - 5 = -16/9(x-(-1)`

`y = -16/9x-16/9+5" "-16/9 = -1 7/9`

`y = -16/9x+3 2/9`