# What is the equation of the line perpendicular to y=9/16x  that passes through  (-1,5) ?

Aug 12, 2016

$y = - \frac{16}{9} x + 3 \frac{2}{9}$

#### Explanation:

A line perpendicular to $y = \frac{9}{16} x$ will have a slope of $- \frac{16}{9}$

So, with $m = - \frac{16}{9} \mathmr{and} \left(- 1 , 5\right)$ we can find the equation from:

$y - {y}_{1} = m \left(x - {x}_{1}\right)$

y - 5 = -16/9(x-(-1)

$y = - \frac{16}{9} x - \frac{16}{9} + 5 \text{ } - \frac{16}{9} = - 1 \frac{7}{9}$

$y = - \frac{16}{9} x + 3 \frac{2}{9}$