# What is the equation of the line that passes through (-2,1)  and is perpendicular to the line that passes through the following points: #(-3,6),(7,-3)?

Jul 16, 2018

$9 y - 10 x - 29 = 0$

#### Explanation:

Gradient of $\left(- 3 , 6\right)$ and $\left(7 , - 3\right)$
${m}_{1} = \frac{6 - - 3}{- 3 - 7} = \frac{9}{-} 10$

For perpendicular lines, ${m}_{1} {m}_{2} = - 1$
so ${m}_{2} = \frac{10}{9}$

$\left(y - 1\right) = \frac{10}{9} \left(x + 2\right)$
$9 y - 9 = 10 x + 20$
$9 y - 10 x - 29 = 0$