What is the equation of the line that passes through (3, 5) and (-7, -6)?

1 Answer
Oct 31, 2017

the equation of the line is 11x-10y+17=0

Explanation:

the given two points are: (x_1,y_1)=(3,5)
(x_2,y_2)=(-7,-6)

the slope is m=(y_2-y_1)/(x_2-x_1)=(-6-5)/(-7-1)=(-10)/-11=10/11
the equation of a line passing through 2 points is
(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)
(y-5)=11/10(x-3)
10(y-5)=11(x-3)
11x-10y+17=0