What is the equation of the line that passes through points (0,1) and (3, 0)?

1 Answer
Jan 30, 2018

See the answer below...

Explanation:

To discuss this question, let a arbitrary point #"P"(x,y)# with whose respect we will determine the equation of the straight line.

  • The slope of a straight line is determined by the following step:-

    If there is two point #"M"(x_1,y_1)# and #"N"(x_2,y_2)# passes through a straight line,the #color(red)("slope of the line"# will be #ul(bar(|color(red)(m=(y_2-y_1)/(x_2-x_1))|#

  • So, we can easily determine the slope of the line by using the above formula. We have variables also to determine slope.

    1) The slope of the line in one hand is
    #color(green)(m=(0-1)/(3-0)=-1/3# where #x_1=0;x_2=3;y_1=1;y_2=0#
    2)The slope of the straight line again is #color(violet)(m=(y-1)/(x-0)=(y-1)/x# where #x_1=0;x_2=x;y_1=1;y_2=y#

Now, we can equalize the slope i.e,

# (y-1)/x=-1/3#
#=>3-3y=x#
#=>color(red)(ul(bar(|color(black)(x+3y=3)|#

Hope the answer helps...
Thank you...

which process I did it, I did not tell you.

It is Two point form.