# What is the equation of the line through point (-4, -5) with slope 3/2?

The equation of the line is $y = \frac{3}{2} \cdot x + 1$
Slope = 3/2; The Equation of the line passing through (-4,-5) having a slope of 3/2 is $y + 5 = \frac{3}{2} \left(x + 4\right) \mathmr{and} y = \frac{3}{2} \cdot x + 6 - 5 \mathmr{and} y = \frac{3}{2} \cdot x + 1$[Ans] graph{3/2*x+1 [-10, 10, -5, 5]}