Question

What is the equation of the line with slope `m= 1/7` that passes through `(-3/11,2/3)`?

Answer 1

`231y = 33x +163`

Explanation:

The general equation for a line is `y= mx +c` where m is the slope and c is the y intercept. So `y = (1/7)x + c`
Substitute in the coordinates of the given point to find c
`2/3 = (1/7)(-3/11) +c`
`c = 2/3 + 3/77`
`c = (2*77 + 3*3)/(3*77)`
`c = 163/231`
`y = (1/7)x + 163/231` or `231y = 33x +163`