# What is the equation of the line with slope  m= 12/11  that passes through  (-2,-8) ?

Jan 15, 2016

The point-slope form is $y + 8 = \frac{12}{11} \left(x + 2\right)$.

#### Explanation:

Use the point-slope equation for a line.

$y - {y}_{1} = m \left(x - x - 1\right)$, where $m$ is the slope, $\frac{12}{11}$, and $\left({x}_{1} , {y}_{1}\right)$ is $\left(- 2 , - 8\right)$

Substitute the given values into the equation.

$y - \left(- 8\right) = \frac{12}{11} \left(x - \left(- 2\right)\right)$

Simplify.

$y + 8 = \frac{12}{11} \left(x + 2\right)$